0=28x^2+26

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Solution for 0=28x^2+26 equation: 



0=28x^2+26

We move all terms to the left:

0-(28x^2+26)=0

We add all the numbers together, and all the variables

-(28x^2+26)=0

We get rid of parentheses

-28x^2-26=0

a = -28; b = 0; c = -26;
Δ = b2-4ac
Δ = 02-4·(-28)·(-26)
Δ = -2912
Delta is less than zero, so there is no solution for the equation

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